33.96=3.14r^2

Solution for 33.96=3.14r^2 equation:

33.96=3.14r^2

We move all terms to the left:

33.96-(3.14r^2)=0

We get rid of parentheses

-3.14r^2+33.96=0

a = -3.14; b = 0; c = +33.96;
Δ = b2-4ac
Δ = 02-4·(-3.14)·33.96
Δ = 426.5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{426.5376}}{2*-3.14}=\frac{0-\sqrt{426.5376}}{-6.28}
=-\frac{\sqrt{}}{-6.28}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{426.5376}}{2*-3.14}=\frac{0+\sqrt{426.5376}}{-6.28}
=\frac{\sqrt{}}{-6.28}
$